Driver side turn signal not working, Weird voltage issue... i think? Options

[Noahwhite2014]

SO my driver side front turn signal is acting up. Ive tried swapping bulbs, same issue. Tried swapping bulb holders, the issue persists. So i know its probably the wiring now... So i pulled out the voltmeter... Stuck the ground into the ground wire pin on the harness plug, and the positive into the left side positive pin on the harness plug (the locking mechanism is at the top, i couldn't see the wire color since it was dark) and i got 25.6V DC... This is supposed to be the DRL light on the corners. I'm not sure if it is supposed to be 25v... but i assume it shouldn't. I didnt have time to test the other side to see if it was also 25v

Then i kept the ground in the same middle pin and the positive to the right side pin on the harness, nothing happened so i assumed it was the turn signal. Popped on the turn signal and got the hyper flash since there was no bulb in. But anyway i pulled 12v off that. Couldn't really read accurately since it was going on and off so quick that the voltmeter hardly had time to read it.

So based off the voltages (assuming the 25v is correct for DRLs...) I SHOULD be getting a DRL and turn signal. BUT i only get a DRL, the turn signal shuts off the DRL light when it is supposed to flash. When the DRLs are off and i try to signal, The DRL filament will come on instead of the turn signal filament (so its dim). I forget to test the voltage on the DRL pin and the turn signal pin with the DRL's off.


Anyone had this issue before? Any ideas on what else to test?

[Box]

I'm officially losing my mind, I had a nice detailed post and it didn't post apparently... Long story short, circuits make the power sources independent. Voltage is potential energy and can be manipulated depending on how it's configured. So inside of a circuit, for example your front marker light, you have a common ground and two sources of 12V. Should one cross into the common ground when both circuits are sent power it makes a connection in series and doubles the voltage.

[Noahwhite2014]

I'm officially losing my mind, I had a nice detailed post and it didn't post apparently... Long story short, circuits make the power sources independent. Voltage is potential energy and can be manipulated depending on how it's configured. So inside of a circuit, for example your front marker light, you have a common ground and two sources of 12V. Should one cross into the common ground when both circuits are sent power it makes a connection in series and doubles the voltage.

Thats what I was thinking, lol I did a little experiment before reading your post. I was trying to double the voltage of a 1.5v battery. Basically I got two wires on both the positive and negative end of the battery holder. Hooked up one pair of wire leads to it. Of course it said 1.54v +-.02v. Then I shorted the other pair of wires quickly. Voltage changed, but it was minor. Did it again, and I got 0. Then I did it multiple times quickly and got it to change a bit lower, some a bit higher. But not much

I appreciate the replies